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debug: Change debug logs to info level to see stdout content
Need to see what .contacts returns (stdout has 10557 chars but JSON parsing fails). 🤖 Generated with [Claude Code](https://claude.com/claude-code) Co-Authored-By: Claude Sonnet 4.5 <noreply@anthropic.com>
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+3
-3
@@ -656,8 +656,8 @@ def get_contacts_json() -> Tuple[bool, Dict[str, Dict], str]:
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# Debug logging to diagnose empty output
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logger.info(f".contacts result: success={success}, stdout_len={len(stdout)}, stderr_len={len(stderr)}")
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logger.debug(f".contacts stdout preview (first 500 chars): {stdout[:500] if stdout else 'EMPTY'}")
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logger.debug(f".contacts stderr: {stderr if stderr else 'EMPTY'}")
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logger.info(f".contacts stdout preview (first 500 chars): {stdout[:500] if stdout else 'EMPTY'}")
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logger.info(f".contacts stderr: {stderr if stderr else 'EMPTY'}")
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if not success:
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logger.error(f".contacts command failed: {stderr}")
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@@ -676,7 +676,7 @@ def get_contacts_json() -> Tuple[bool, Dict[str, Dict], str]:
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return True, contacts_dict, ""
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except json.JSONDecodeError as e:
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logger.error(f"Failed to parse .contacts JSON output: {e}")
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logger.debug(f"Problematic JSON string (first 1000 chars): {stdout[:1000]}")
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logger.error(f"Problematic JSON string (first 1000 chars): {stdout[:1000]}")
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return False, {}, f'JSON parse error: {e}'
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except Exception as e:
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